Does this actually work?

[Kaalia with haste]

I've recently been toying with the idea of a {melek, izzet paragon} EDH deck and was thinking of the best way to abuse mystical tutor and this seems too good to be true so I wanted to check:

Board: melek and 5-7 lands

Top of my library: mystical tutor.

So I cast mystical tutor and copy it and when the first one resolves seething song goes on top of my library, with the other one on the stack I cast seething song and copy it adding RRRRRRRRRR to my pool. Then the second mystical tutor resolves and I put stroke of genius on top of my library (or mind spring or any draw X) and then cast stroke of genius X = 10 and copy it to draw 20 cards. Please tell me this works it seems so awesome!

[Kaylesh]

I've recently been toying with the idea of a {melek, izzet paragon} EDH deck and was thinking of the best way to abuse mystical tutor and this seems too good to be true so I wanted to check:

Board: melek and 5-7 lands

Top of my library: mystical tutor.

So I cast {mystical tutor} and copy it and when the first one resolves {seething song} goes on top of my library, with the other one on the stack I cast seething song and copy it adding RRRRRRRRRR to my pool. Then the second mystical tutor resolves and I put {stroke of genius} on top of my library (or mind spring or any draw X) and then cast stroke of genius X = 10 and copy it to draw 20 cards. Please tell me this works it seems so awesome!

Seems legit. You could also tutor a sorcery like {disintegrate}. Deal 18 dam + 2 added for each {R} you manage to generate. Who was that mountain planes walker again?  {Koth of the Hammer}. One turn kill if you can float enough mana.

[LinkCelestrial]

Melek rules on X cost? Most things copy it as X = 0. Otherwise seems legit as you get to respond between spells resolving.

[particle]

Melek rules on X cost? Most things copy it as X = 0. Otherwise seems legit as you get to respond between spells resolving.

Your thinking of "Casting a spell without paying its mana cost." In those cases, x is normally zero. However, melek doesnt let you cast them for free, he simply gives you another location to cast spells from. Now if your talking about the copying of spells, melek will keep the x from the original. If you were made to "cast the copy" it would be different, but the copy will see the locked in amount for x and use that.

[LinkCelestrial]

Melek rules on X cost? Most things copy it as X = 0. Otherwise seems legit as you get to respond between spells resolving.

Your thinking of "Casting a spell without paying its mana cost." In those cases, x is normally zero. However, melek doesnt let you cast them for free, he simply gives you another location to cast spells. Now if your talking about the copying of spells, melek will keep the x from the original. If you were made to "cast the copy" it would be different, but the copy will see the locked in amount for x and use that.

Okay sweet, makes more sense now. Thanks.