{venser the sojourner} + {doubling season} and any planeswalker applicable like {chandra nalaar}
Quote from: Wackaman9001 on March 16, 2013, 04:52:50 PM
{venser the sojourner} + {doubling season} and any planeswalker applicable like {chandra nalaar}
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{Doubling season} does not double loyalty counters as the are a cost of the abillity not an affect of it, the plsneswalker that can increase its loyalty counters with {doubling season} is {Gideon, Champion of Justice}, as his first ability adds loyalty counters, in addition to its cost,
You misunderstand, they enter with double, and some can ulti at that point. You ulti, then use venser's +2 to exile them. At the end step they return like just cast, and so have double counters, ready to do it again next turn
This does work. Personally I prefer the {jace, architect of thought} chain where you grab a new jace and their best card then end on {emrakul, the aeons torn} or something. {tamiyo the moon sage} makes this infinite.
Nice.
Is this really how doubling season is suppose to interact with planeswalkers when they ETB? If so I need to get {Garruk, Caller of Beasts} and I might just put {Liliana Vess} back in my golgari EDH.
{Sorin Markov} GG!
{Ral Zarek} or {Sorin Markov}
Infinite turns!!!
Quote from: The1337Magician on August 13, 2013, 06:03:19 PM
{Ral Zarek} or {Sorin Markov}
Infinite turns!!!
True story!!
Quote from: Taysby on August 13, 2013, 06:32:16 PM
Ral zarek might not give you infinite turns. Most likely it will, but there is a chance it won't.
1/6 chance of getting no extra turns. You gotta be pretty unlucky to flip 5 tails In a row.
You definitely need pretty bad luck to fail to get at least one extra turn. On the other hand, 1/6 is not that low a chance. Or the right one. It's 1/32. Or roughly 97% chance of at least one coin coming up heads.
16%chance not to get an xtra turn compared to 84% to get atleast 1 xtra turn.
Quote from: Taysby on August 13, 2013, 06:32:16 PM
Ral zarek might not give you infinite turns. Most likely it will, but there is a chance it won't.
Throw a {Krark's Thumb} in there to make it almost impossible to not get an extra turn.
Don't forget {chance encounter} then lol
Quote from: Double-O-Scotch on August 14, 2013, 01:16:32 PM
Don't forget {chance encounter} then lol
Does {Ral Zarek}'s ulti count as winning a coin flip? If so, that's a cool combo.
Quote from: Leevai420 on August 13, 2013, 09:42:02 PM
Quote from: Taysby on August 13, 2013, 06:32:16 PM
Ral zarek might not give you infinite turns. Most likely it will, but there is a chance it won't.
1/6 chance of getting no extra turns. You gotta be pretty unlucky to flip 5 tails In a row.
Like I did, every game of the pretelease!
Quote from: Leevai420 on August 13, 2013, 11:19:10 PM
16%chance not to get an xtra turn compared to 84% to get atleast 1 xtra turn.
Probability of a tail in one flip =0.5
A second tail = 0.5*0.5.=0.25
5 tails= (.5)^ 5=0.03125
If there's any special conditions I'm missing I'd love to hear it, but this is fairly clean and simple probabilities.
Mlerner, try old quarters. They lean toward more heads.
I second this. Old quarters are more likely to come up heads than tails.
Quote from: Arcadi_tepes on August 15, 2013, 03:50:12 PM
Quote from: Leevai420 on August 13, 2013, 11:19:10 PM
16%chance not to get an xtra turn compared to 84% to get atleast 1 xtra turn.
Probability of a tail in one flip =0.5
A second tail = 0.5*0.5.=0.25
5 tails= (.5)^ 5=0.03125
If there's any special conditions I'm missing I'd love to hear it, but this is fairly clean and simple probabilities.
Mlerner, try old quarters. They lean toward more heads.
I'm looking at the probability of your results. You can only have 1 of 6 result from talks ultimate.
HHHHH
TTTTT
HHHHT
TTTTH
HHTTT
TTHHH
So like I said 1/6 chance of getting no turns.
Quote from: Leevai420 on August 15, 2013, 05:55:46 PM
Quote from: Arcadi_tepes on August 15, 2013, 03:50:12 PM
Quote from: Leevai420 on August 13, 2013, 11:19:10 PM
16%chance not to get an xtra turn compared to 84% to get atleast 1 xtra turn.
Probability of a tail in one flip =0.5
A second tail = 0.5*0.5.=0.25
5 tails= (.5)^ 5=0.03125
If there's any special conditions I'm missing I'd love to hear it, but this is fairly clean and simple probabilities.
Mlerner, try old quarters. They lean toward more heads.
I'm looking at the probability of your results. You can only have 1 of 6 result from talks ultimate.
HHHHH
TTTTT
HHHHT
TTTTH
HHTTT
TTHHH
So like I said 1/6 chance of getting no turns.
Your math is flawed, sir.
Guys there is 1/6chance 5 heads 4 heads 3 heads 2 heads 1heads 0head now referring back tousle school u divide 6 into 1 giving u 0.16 the six repeating or if u round 0.17 now u put it into precent making it 17% u don't get any heads
Flipping a heads =.5 chance yes?
.5^6 = .015625 or about 1.6% , highly unlikely
Quote from: Wackaman9001 on August 15, 2013, 07:22:18 PM
Flipping a heads =.5 chance yes?
.5^6 = .015625 or about 1.6% , highly unlikely
You don't do the percentage per flip. Your always going to have a 50/50 chance when you flip the coin. But because you flip it 5x you tally the total possible results instead of the individual flip.
Its the same math as rolling 3 dice and each ending on a 1, or at least the same concept. You can test it if you would like but the math is sound.
Quote from: Leevai420 on August 15, 2013, 05:55:46 PM
I'm looking at the probability of your results. You can only have 1 of 6 result from talks ultimate.
HHHHH
TTTTT
HHHHT
TTTTH
HHTTT
TTHHH
So like I said 1/6 chance of getting no turns.
You forgot
HTHTH
THTHT
THTTT
HTTTT
TTHTT
TTTHT
TTTTH
etc.
The order doesn't matter just the total number of possible heads and tails in 5 flips of a coin. Those are the odds you go by.
Quote from: Leevai420 on August 16, 2013, 12:31:49 AM
The order doesn't matter just the total number of possible heads and tails in 5 flips of a coin. Those are the odds you go by.
The order maters in the sense that you are ignoring possible outcomes. HTHTH and HTTHH are two possible events not one. In other words, you are right that there's only 6 types of outcomes, but the probabilities of each are not the same. Seriously, try it. By your count there's 33% chance of a HH or HT or TT with two flips, rather than 25% of HH, HT, TH, or TT. Does experimenting pan out on those numbers?
Quote from: Arcadi_tepes on August 16, 2013, 12:44:45 AM
Quote from: Leevai420 on August 16, 2013, 12:31:49 AM
The order doesn't matter just the total number of possible heads and tails in 5 flips of a coin. Those are the odds you go by.
The order maters in the sense that you are ignoring possible outcomes. HTHTH and HTTHH are two possible events not one. In other words, you are right that there's only 6 types of outcomes, but the probabilities of each are not the same. Seriously, try it. By your count there's 33% chance of a HH or HT or TT with two flips, rather than 25% of HH, HT, TH, or TT. Does experimenting pan out on those numbers?
As I've always been taught it doesn't matter. This is a COMBINATION, not PERMUTATION, order does not matter.
Quote from: Arcadi_tepes on August 16, 2013, 12:50:49 AM
Quote from: Mlerner12 on August 16, 2013, 12:49:06 AM
Quote from: Arcadi_tepes on August 16, 2013, 12:44:45 AM
Quote from: Leevai420 on August 16, 2013, 12:31:49 AM
The order doesn't matter just the total number of possible heads and tails in 5 flips of a coin. Those are the odds you go by.
The order maters in the sense that you are ignoring possible outcomes. HTHTH and HTTHH are two possible events not one. In other words, you are right that there's only 6 types of outcomes, but the probabilities of each are not the same. Seriously, try it. By your count there's 33% chance of a HH or HT or TT with two flips, rather than 25% of HH, HT, TH, or TT. Does experimenting pan out on those numbers?
As I've always been taught it doesn't matter. This is a COMBINATION, not OERMUTATION, order does not matter.
You didn't say anything.
Quote from: Mlerner12 on August 16, 2013, 12:52:30 AM
Quote from: Arcadi_tepes on August 16, 2013, 12:50:49 AM
Quote from: Mlerner12 on August 16, 2013, 12:49:06 AM
Quote from: Arcadi_tepes on August 16, 2013, 12:44:45 AM
Quote from: Leevai420 on August 16, 2013, 12:31:49 AM
The order doesn't matter just the total number of possible heads and tails in 5 flips of a coin. Those are the odds you go by.
The order maters in the sense that you are ignoring possible outcomes. HTHTH and HTTHH are two possible events not one. In other words, you are right that there's only 6 types of outcomes, but the probabilities of each are not the same. Seriously, try it. By your count there's 33% chance of a HH or HT or TT with two flips, rather than 25% of HH, HT, TH, or TT. Does experimenting pan out on those numbers?
As I've always been taught it doesn't matter. This is a COMBINATION, not OERMUTATION, order does not matter.
You didn't say anything.
Combination gets you the possible outcomes ignoring permutations yes. But this does not in anyway inform you of the probabilities of each combination. Which are not the same. The point is not to figure out the combinations of 5 flips. The point is the probability of a unique permutation. That is, there is only one permutation of HHHHH out of 32 permutations. And only one TTTTT. But there are several HTTTT permutations. Five in fact. And even more HHTTT. The probabilities of these are much greater than that of TTTTT.
Edit: sorry, almost dropped tablet, pushed wrong thing.
Similar situation - odds of rolling a 2 on 2d6.
Is it 1/36 or 1/21?
The right answer is 1/36. There are some people who incorrectly assume its 1/21.